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Timeline for A well-founded relation on lists

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Mar 12, 2015 at 8:30 comment added Paul Taylor OK I'll think about that, but I am pretty confident that the result in my paper has to be the core of the solution.
Mar 11, 2015 at 23:27 comment added Mike Shulman I don't see why the map $L A \to K A$ preserves $\prec$. For instance, if $A=\mathbb{N}$ with its usual ordering, then in $L A$ we have $(3,0) \prec (3,1)$, but I don't think we have $\{3,0\} \prec \{3,1\}$ in $K A$: for $u=3\in \{3,0\}$ there is no $v\in \{3,1\}$ such that $3\prec v$.
Mar 10, 2015 at 14:45 history edited Paul Taylor CC BY-SA 3.0
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Mar 10, 2015 at 9:36 history answered Paul Taylor CC BY-SA 3.0