Timeline for Convexity of a (non-symmetric) function of matrices
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Mar 9, 2015 at 16:22 | comment | added | Suvrit | More easily, this also follows from Jacobi's identity: $\det(A[S]) = \det(A)\det(A^{-1}[\bar{S}]$, where $A[S]$ is the principal submatrix index by $S$, which $\bar{S}$ denotes the complement of $S$. | |
| Mar 9, 2015 at 16:20 | vote | accept | Vamsi | ||
| Mar 9, 2015 at 3:45 | history | answered | Suvrit | CC BY-SA 3.0 |