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Aug 29, 2015 at 13:49 answer added jjms timeline score: 3
Mar 9, 2015 at 10:14 comment added user74230 The answer to the final question is affirmative, but for reasons specific to that situation. Namely, if $B \otimes_A k$ is a separable closure of $k$ then $B$ has to be the completion of a strict henselization $A^{\rm{sh}}$ of $A$, so it suffices to show that $A^{\rm{sh}}$ is excellent. But $A$ is excellent since it is complete local noetherian (EGA IV$_3$, 7.8.3(iii)), and strict henselization preserves excellence of local rings (though EGA IV$_4$, 18.7.6 handles henselization, curiously EGA does not handle the analogue for strict henselization; see p. 17 of Freitag-Kiehl for a proof).
Mar 8, 2015 at 21:57 history asked Olórin CC BY-SA 3.0