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Nov 26, 2019 at 8:40 comment added Andrej Bauer A useful point of view is that the open subsets of $X$ are in bijective correspondence with continuous maps $X \to \Sigma$ where $\Sigma$ is the Sierpinski space. Compactness can be expressed in terms of such maps.
Mar 10, 2015 at 1:47 comment added Oleg Viro Dear Qiaochu Yuan, thanks for the reference to ncatlab. Unfortunately, they failed to deal with the true compactness of topological spaces.
Mar 9, 2015 at 12:30 comment added user13113 You may find the notion of a Grothendieck topology interesting.
Mar 9, 2015 at 11:06 answer added Paul Taylor timeline score: 0
Mar 9, 2015 at 5:59 comment added Qiaochu Yuan Regarding the edit, perhaps ncatlab.org/nlab/show/compact+object might be helpful.
Mar 9, 2015 at 5:42 vote accept Oleg Viro
Mar 9, 2015 at 5:42 vote accept Oleg Viro
Mar 9, 2015 at 5:42
Mar 9, 2015 at 5:41 history edited Oleg Viro CC BY-SA 3.0
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Mar 9, 2015 at 5:13 vote accept Oleg Viro
Mar 9, 2015 at 5:42
Mar 9, 2015 at 5:13 vote accept Oleg Viro
Mar 9, 2015 at 5:13
Mar 9, 2015 at 5:09 vote accept Oleg Viro
Mar 9, 2015 at 5:13
Mar 9, 2015 at 5:05 vote accept Oleg Viro
Mar 9, 2015 at 5:07
Mar 9, 2015 at 5:04 vote accept Oleg Viro
Mar 9, 2015 at 5:05
Mar 9, 2015 at 5:03 vote accept Oleg Viro
Mar 9, 2015 at 5:04
Mar 9, 2015 at 3:53 comment added Eric Wofsey You want to require that the images of the $f_i$ cover $X$; otherwise any discrete space has this property (you can always just take the empty subfamily).
Mar 9, 2015 at 3:39 answer added Eric Wofsey timeline score: 18
Mar 9, 2015 at 2:59 answer added Dave Witte Morris timeline score: 14
Mar 8, 2015 at 22:17 comment added Todd Trimble Welcome to MathOverflow, Professor Viro.
Mar 8, 2015 at 21:28 review First posts
Mar 8, 2015 at 21:38
Mar 8, 2015 at 21:26 history asked Oleg Viro CC BY-SA 3.0