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Mar 9, 2015 at 21:57 comment added MrSelberg Well, I answered the past question, where the increasing condition is't there. This is a 'little bit' new question (see the editions).
Mar 9, 2015 at 21:42 comment added Fedor Petrov But $f$ increases
Mar 9, 2015 at 19:31 history edited MrSelberg CC BY-SA 3.0
Expand answer + typo + spelling
Mar 8, 2015 at 17:00 comment added MrSelberg You are right @Cristian, I forgot that hypothesis.
Mar 8, 2015 at 16:51 comment added Christian Remling I don't think this will satisfy $g(2\pi)=g(0)$ though.
Mar 8, 2015 at 16:17 history answered MrSelberg CC BY-SA 3.0