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Glorfindel
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I can construct a finitely presented group $G$ with the following property (which I use to construct something else).

Given a finitely preseted group $\Gamma$, there is a subgroup $G'\le G$ of finite index such that $$\Gamma=G'/\langle\mathrm{Tor}\, G'\rangle ,$$ where $\mathrm{Tor}\, G'\subset G'$ is the set of all elements of finite order.

I think to call such group $G$ universal.

Questions:

  • Was it already constructed?
  • Does it already has a name? Is there any closely related terminology?

P.S.

  • The group which I construct is in fact hyperbolic.
  • The construction is simple, but it takes 2--3 pages. Let me know if you see a short way to do it.
  • Here, the term "universal group" was used in very similar context (thanks to D. Panov for the reference).
  • Thanks to all your comments, we call them "telescopic" actions"telescopic" actions now.

I can construct a finitely presented group $G$ with the following property (which I use to construct something else).

Given a finitely preseted group $\Gamma$, there is a subgroup $G'\le G$ of finite index such that $$\Gamma=G'/\langle\mathrm{Tor}\, G'\rangle ,$$ where $\mathrm{Tor}\, G'\subset G'$ is the set of all elements of finite order.

I think to call such group $G$ universal.

Questions:

  • Was it already constructed?
  • Does it already has a name? Is there any closely related terminology?

P.S.

  • The group which I construct is in fact hyperbolic.
  • The construction is simple, but it takes 2--3 pages. Let me know if you see a short way to do it.
  • Here, the term "universal group" was used in very similar context (thanks to D. Panov for the reference).
  • Thanks to all your comments, we call them "telescopic" actions now.

I can construct a finitely presented group $G$ with the following property (which I use to construct something else).

Given a finitely preseted group $\Gamma$, there is a subgroup $G'\le G$ of finite index such that $$\Gamma=G'/\langle\mathrm{Tor}\, G'\rangle ,$$ where $\mathrm{Tor}\, G'\subset G'$ is the set of all elements of finite order.

I think to call such group $G$ universal.

Questions:

  • Was it already constructed?
  • Does it already has a name? Is there any closely related terminology?

P.S.

  • The group which I construct is in fact hyperbolic.
  • The construction is simple, but it takes 2--3 pages. Let me know if you see a short way to do it.
  • Here, the term "universal group" was used in very similar context (thanks to D. Panov for the reference).
  • Thanks to all your comments, we call them "telescopic" actions now.
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Anton Petrunin
  • 45k
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I can construct a finitely presented group $G$ with the following property (which I use to construct something else).

Given a finitely preseted group $\Gamma$, there is a subgroup $G'\le G$ of finite index such that $$\Gamma=G'/\langle\mathrm{Tor}\\, G'\rangle ,$$$$\Gamma=G'/\langle\mathrm{Tor}\, G'\rangle ,$$ where $\mathrm{Tor}\\, G'\subset G'$$\mathrm{Tor}\, G'\subset G'$ is the set of all elements of finite order.

I think to call such group $G$ universal.

Questions:

  • Was it already constructed?
  • Does it already has a name? Is there any closely related terminology?

P.S.

  • The group which I construct is in fact hyperbolic.
  • MyThe construction is simple, but it takes 2--3 pages. Let me know if you see a short way to do it.
  • Here, the term "universal group" was used in very similar context (thanks to D. Panov for the reference).
  • Thanks to all your comments, we call them "all-inclusive""telescopic" actions now.

I can construct a finitely presented group $G$ with the following property (which I use to construct something else).

Given a finitely preseted group $\Gamma$, there is a subgroup $G'\le G$ of finite index such that $$\Gamma=G'/\langle\mathrm{Tor}\\, G'\rangle ,$$ where $\mathrm{Tor}\\, G'\subset G'$ is the set of all elements of finite order.

I think to call such group $G$ universal.

Questions:

  • Was it already constructed?
  • Does it already has a name? Is there any closely related terminology?

P.S.

  • The group which I construct is in fact hyperbolic.
  • My construction is simple, but it takes 2--3 pages. Let me know if you see a short way to do it.
  • Here, the term "universal group" was used in very similar context (thanks to D. Panov for the reference).
  • Thanks to all your comments, we call them "all-inclusive" actions now.

I can construct a finitely presented group $G$ with the following property (which I use to construct something else).

Given a finitely preseted group $\Gamma$, there is a subgroup $G'\le G$ of finite index such that $$\Gamma=G'/\langle\mathrm{Tor}\, G'\rangle ,$$ where $\mathrm{Tor}\, G'\subset G'$ is the set of all elements of finite order.

I think to call such group $G$ universal.

Questions:

  • Was it already constructed?
  • Does it already has a name? Is there any closely related terminology?

P.S.

  • The group which I construct is in fact hyperbolic.
  • The construction is simple, but it takes 2--3 pages. Let me know if you see a short way to do it.
  • Here, the term "universal group" was used in very similar context (thanks to D. Panov for the reference).
  • Thanks to all your comments, we call them "telescopic" actions now.
deleted 17 characters in body
Source Link
Anton Petrunin
  • 45k
  • 14
  • 135
  • 299

I can construct a finitely presented group $G$ with the following property (which I use to construct something else).

Given a finitely preseted group $\Gamma$, there is a subgroup $G'\le G$ of finite index such that $$\Gamma=G'/\langle\mathrm{Tor}\\, G'\rangle ,$$ where $\mathrm{Tor}\\, G'\subset G'$ is the set of all elements of finite order.

I think to call such group $G$ universal.

Questions:

  • Was it already constructed?
  • Does it already has a name? Is there any closely related terminology?

P.S.

  • The group which I construct is in fact hyperbolic.
  • My construction is simple, but it takes 2--3 pages. Let me know if you see a short way to do it.
  • Here, the term "universal group" was used in very similar context (thanks to D. Panov for the reference).
  • Thanks to all your comments, we decided to call it "telescopic"; seethem Telescopic"all-inclusive" actions now.

I can construct a finitely presented group $G$ with the following property (which I use to construct something else).

Given a finitely preseted group $\Gamma$, there is a subgroup $G'\le G$ of finite index such that $$\Gamma=G'/\langle\mathrm{Tor}\\, G'\rangle ,$$ where $\mathrm{Tor}\\, G'\subset G'$ is the set of all elements of finite order.

I think to call such group $G$ universal.

Questions:

  • Was it already constructed?
  • Does it already has a name? Is there any closely related terminology?

P.S.

  • The group which I construct is in fact hyperbolic.
  • My construction is simple, but it takes 2--3 pages. Let me know if you see a short way to do it.
  • Here, the term "universal group" was used in very similar context (thanks to D. Panov for the reference).
  • Thanks to all your comments, we decided to call it "telescopic"; see Telescopic actions

I can construct a finitely presented group $G$ with the following property (which I use to construct something else).

Given a finitely preseted group $\Gamma$, there is a subgroup $G'\le G$ of finite index such that $$\Gamma=G'/\langle\mathrm{Tor}\\, G'\rangle ,$$ where $\mathrm{Tor}\\, G'\subset G'$ is the set of all elements of finite order.

I think to call such group $G$ universal.

Questions:

  • Was it already constructed?
  • Does it already has a name? Is there any closely related terminology?

P.S.

  • The group which I construct is in fact hyperbolic.
  • My construction is simple, but it takes 2--3 pages. Let me know if you see a short way to do it.
  • Here, the term "universal group" was used in very similar context (thanks to D. Panov for the reference).
  • Thanks to all your comments, we call them "all-inclusive" actions now.
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Anton Petrunin
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Anton Petrunin
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Anton Petrunin
  • 45k
  • 14
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  • 299
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Anton Petrunin
  • 45k
  • 14
  • 135
  • 299
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