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Mar 31, 2010 at 0:18 comment added BCnrd Serre proves that the module-finiteness condition for integral closure holds when the extension of fraction fields is separable, so in the context of the question $S$ is automatically module-finite over $R$. These matters can also be considered from the viewpoint of valuation theory, allowing for the possibility of non-archimedean valuations which are not discretely-valued. See 3.6/5,6 in "Non-archimedean analysis" by Bosch, Guntzer, Remmert.
Mar 31, 2010 at 0:06 vote accept Randy Brown
Mar 30, 2010 at 23:25 history answered Ari Shnidman CC BY-SA 2.5