Timeline for $u_n$ bounded in $L^\infty(0,T;H) \cap L^2(0,T;V)$ implies $u_n \to u$ strongly in $L^2(0,T;H)$?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Mar 4, 2015 at 8:06 | vote | accept | Charpe | ||
| Mar 3, 2015 at 7:35 | answer | added | Jean Van Schaftingen | timeline score: 1 | |
| Mar 2, 2015 at 19:23 | history | edited | Charpe | CC BY-SA 3.0 |
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| Mar 2, 2015 at 18:13 | comment | added | Charpe | @Corbennick please see edit. It comes from the first two bounds. | |
| Mar 2, 2015 at 18:12 | history | edited | Charpe | CC BY-SA 3.0 |
added 61 characters in body
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| Mar 2, 2015 at 18:07 | comment | added | user1688 | Where does $u$ come from? A simple counterexample is obtained from letting the sequence oscillate between two vectors. | |
| Mar 2, 2015 at 18:06 | review | First posts | |||
| Mar 2, 2015 at 18:13 | |||||
| Mar 2, 2015 at 18:04 | history | asked | Charpe | CC BY-SA 3.0 |