Skip to main content
9 events
when toggle format what by license comment
Mar 2, 2015 at 23:23 comment added Jim Humphreys @Amir: Your definition of "simply connected" is too narrow for this kind of question, which makes sense and has a similar easy answer over any algebraically closed field. Aside from that, there are already questions on MO which cover similar ground in a more refined style. Search for "simply connected" [algebraic-groups].
Mar 2, 2015 at 23:11 history closed Venkataramana
YCor
Joonas Ilmavirta
abx
Johannes Hahn
Not suitable for this site
Mar 2, 2015 at 19:33 vote accept Amir
Mar 2, 2015 at 17:23 answer added Dave Witte Morris timeline score: 3
Mar 2, 2015 at 17:19 history edited Max Horn CC BY-SA 3.0
Make sure title and question match
Mar 2, 2015 at 17:08 review Close votes
Mar 2, 2015 at 23:11
Mar 2, 2015 at 16:54 comment added Venkataramana No. $H$ need not be simply connected
Mar 2, 2015 at 16:18 review First posts
Mar 2, 2015 at 16:19
Mar 2, 2015 at 16:18 history asked Amir CC BY-SA 3.0