Timeline for Can you write $\mathbb R^2$ as a disjoint union of two totally disconnected sets?
Current License: CC BY-SA 3.0
8 events
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Apr 27, 2016 at 13:30 | comment | added | Lasse Rempe | But actually, as noted in the question there, the result (any disconnected subset of the plane can be disconnected by a closed connected set) does not require any assumption of closedness / compactness. (See also the answer I just gave there.) So this does in fact answer the question. | |
| Feb 27, 2015 at 1:35 | history | undeleted | Kristal Cantwell | ||
| Feb 26, 2015 at 22:41 | history | deleted | Kristal Cantwell | via Vote | |
| Feb 26, 2015 at 21:53 | comment | added | Włodzimierz Holsztyński | @EricWofsey -- for a contrast, your own (transcendental) example in the other (path) thread was super ! | |
| Feb 25, 2015 at 20:53 | comment | added | Eric Wofsey | That answer only applies to closed sets, in which case the question asked here is trivial since no nonempty open set is totally disconnected. | |
| Feb 25, 2015 at 20:06 | history | edited | Kristal Cantwell | CC BY-SA 3.0 |
adding detail
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| Feb 25, 2015 at 19:57 | history | answered | Kristal Cantwell | CC BY-SA 3.0 |