Timeline for A list of machineries for computing cohomology
Current License: CC BY-SA 2.5
12 events
| when toggle format | what | by | license | comment | |
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| Apr 1, 2010 at 10:46 | answer | added | Lennart Meier | timeline score: 5 | |
| Mar 31, 2010 at 0:00 | answer | added | shenghao | timeline score: 8 | |
| Mar 30, 2010 at 19:20 | history | edited | Sean Tilson | CC BY-SA 2.5 |
edited basic section
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| Mar 30, 2010 at 18:10 | comment | added | Kevin H. Lin | Despite the first sentence, this is a question. | |
| Mar 30, 2010 at 18:07 | answer | added | Kevin H. Lin | timeline score: 14 | |
| Mar 30, 2010 at 17:50 | comment | added | Kim Morrison | I've tagged as big-list and set as community-wiki, per the discussions at tea.mathoverflow.net/discussion/100 and tea.mathoverflow.net/discussion/247. | |
| Mar 30, 2010 at 17:49 | history | edited | Kim Morrison |
tagging big-list and setting as community-wiki; Post Made Community Wiki
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| Mar 30, 2010 at 17:47 | history | edited | Bo Peng |
edited tags
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| Mar 30, 2010 at 17:23 | comment | added | S. Carnahan♦ | Sorry, I'm voting to close. Reason: not a real question (cf. your first sentence). | |
| Mar 30, 2010 at 17:05 | history | edited | Bo Peng | CC BY-SA 2.5 |
added 2 characters in body
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| Mar 30, 2010 at 16:05 | comment | added | Regenbogen | Theoretically, one can use the de Rham theorem and deform the manifold to some other space that is homotopy equivalent to this space, and compute the cohomology of that. Like, all contractible spaces have the cohomology of the point, or the punctured plane and the circle has the same cohomology. This is not a formal machinery; so I am leaving this trivial observation as a comment. | |
| Mar 30, 2010 at 15:56 | history | asked | Bo Peng | CC BY-SA 2.5 |