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Mar 12, 2020 at 18:15 history edited YCor
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Apr 13, 2017 at 12:19 history edited CommunityBot
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Feb 24, 2015 at 12:56 vote accept W4cc0
Feb 24, 2015 at 12:44 answer added Jeremy Rickard timeline score: 17
Feb 24, 2015 at 10:44 comment added j.p. As we may assume $2\cdot A\ne 0$ (all elements having order $2$ is easy), we know that taking the inverse is the unique automorphism of order $2$. In particular, the cyclic automorphism group is finite.
Feb 24, 2015 at 8:28 history asked W4cc0 CC BY-SA 3.0