Timeline for The fundamental group of the complement of codimension 2 submanifold
Current License: CC BY-SA 3.0
7 events
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Feb 22, 2015 at 14:27 | comment | added | ThiKu | I guess one has to invoke the tubular neighborhood theorem to see that all meridians are conjugate to each other. | |
Feb 22, 2015 at 12:50 | comment | added | Alex Degtyarev | Oops! Sorry. Still, this does not seem necessary. One can probably derive this from Zariski--van Kampen, but an easier way is to take a loop $\gamma$ in $V\setminus M$, assume that it bounds a disk, and then make this disk transverse to $M$. Then it's clear that $\gamma$ is the product of a bunch of loops conjugate to the meridian. | |
Feb 22, 2015 at 12:45 | history | edited | user283635 | CC BY-SA 3.0 |
edited title
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Feb 22, 2015 at 12:31 | comment | added | user283635 | The condition is $f_*\colon \pi_1(M)\to \pi_1(V)$ is surjective not $\operatorname{inc}_*\colon \pi_1(V-f(M))\to \pi_1(V)$ is surjective. | |
Feb 22, 2015 at 12:22 | comment | added | Alex Degtyarev | This is not a condition, as it always holds. E.g., because any loop in $V$ can be made disjoint from $M$. | |
Feb 22, 2015 at 11:58 | review | First posts | |||
Feb 22, 2015 at 12:22 | |||||
Feb 22, 2015 at 11:43 | history | asked | user283635 | CC BY-SA 3.0 |