Timeline for Square-free grows as $6n/\pi^2$: $k$-th free?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Feb 22, 2015 at 2:42 | comment | added | Douglas Zare | The analogue holds for the probability that $k$ randomly chosen positive integers (up to $n$, then let $n\to \infty$) are relatively prime. J.E Nymann. "On the probability that k positive integers are relatively prime." Journal of Number Theory Volume 4, Issue 5, October 1972, Pages 469–473. A similar result is known for the probability that $k$ positive integers are pairwise coprime. | |
| Feb 22, 2015 at 2:07 | vote | accept | Joseph O'Rourke | ||
| Feb 22, 2015 at 2:06 | history | edited | Joseph O'Rourke | CC BY-SA 3.0 |
added 16 characters in body
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| Feb 22, 2015 at 2:03 | answer | added | Noam D. Elkies | timeline score: 9 | |
| Feb 22, 2015 at 1:59 | history | edited | Joseph O'Rourke | CC BY-SA 3.0 |
Answered.
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| Feb 22, 2015 at 1:02 | comment | added | Gjergji Zaimi | Yes, your guess of $1/\zeta(k)$ is correct :) en.wikipedia.org/wiki/… | |
| Feb 22, 2015 at 0:55 | history | asked | Joseph O'Rourke | CC BY-SA 3.0 |