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Feb 13, 2015 at 17:36 history edited Gottfried Helms CC BY-SA 3.0
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Feb 13, 2015 at 3:27 history edited Gottfried Helms CC BY-SA 3.0
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Feb 13, 2015 at 3:24 comment added Gottfried Helms @GerryMyerson: the first column contains the denominators of the zeta at 0 and then at the even nonpositive indexes, where of course the zeta is zero, and the "denominator" is normalized to be 1 (as provided by Pari/GP). I possibly should have omitted that column...
Feb 13, 2015 at 3:06 comment added Gerry Myerson I'm not sure what your leftmost column of $1$s is about. In any event, von Staudt-Clausen only gives the denominator of $2k\zeta(1-2k)$; for the denominator of $\zeta(1-2k)$, you need another theorem of von Staudt, as indicated in my answer.
Feb 13, 2015 at 2:57 history answered Gottfried Helms CC BY-SA 3.0