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Feb 9, 2015 at 0:28 history edited GH from MO CC BY-SA 3.0
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Feb 8, 2015 at 23:52 history edited GH from MO CC BY-SA 3.0
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Feb 8, 2015 at 23:48 comment added GH from MO You are right, let me fix this.
Feb 8, 2015 at 23:43 comment added R.P. Wait, shouldn't $K$ be the union of all Galois extensions of $2$-power degree over $\mathbb{Q}$? I don't think the set of all algebraic numbers of $2$-power degree forms a field (e.g. any two degree-$4$ subextensions of an $S_4$-extension give rise to a degree-$12$ compositum...).
Feb 8, 2015 at 22:10 comment added GH from MO @LutzMattner: I don't think you will find a reference for the claim in my added section, but the proof should be a straightforward adaptation or consequence of what is written.
Feb 8, 2015 at 21:58 comment added GH from MO @LutzMattner: See my added section.
Feb 8, 2015 at 21:58 history edited GH from MO CC BY-SA 3.0
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Feb 8, 2015 at 21:46 comment added Lutz Mattner I dont' think so. From points just in the $x$-$y$-plane you can not construct any point not belonging to it.
Feb 8, 2015 at 21:42 history edited GH from MO CC BY-SA 3.0
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Feb 8, 2015 at 21:37 comment added GH from MO @LutzMattner: A physically given cube determines three distances between their vertices: each of these is constructible from the edge length, so the problem told by the oracle of Delos is equivalent to the one I described. Note that a compass is designed for plane drawings.
Feb 8, 2015 at 21:34 comment added Lutz Mattner Well, but this does not fit well to the story of the oracle of Delos asking for the doubling of a certain physically given cube.
Feb 8, 2015 at 21:32 history answered GH from MO CC BY-SA 3.0