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S May 2, 2020 at 12:55 history bounty started Ali Taghavi
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S Jan 27, 2017 at 18:39 history bounty started Ali Taghavi
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Nov 13, 2016 at 8:56 comment added Ali Taghavi @JohannesHahn Thanks for your comment. As you pointed out a minimal dynamical system gives a simple C* algebra. But what about the spectrum of its elements(Path connected spectrum)?
Nov 7, 2016 at 19:47 comment added Ali Taghavi @HannesThiel Thank you very much for your comment and your attention. The motivation for the second part of my question, about the reduced $C^*$ algebra, is obvious. Regarding the first part: the motivation is that the product topology of two path connected space is a path connected space. But according to your comment, one can ask that: Is the tensor product of two idempotent less C* algebras, an idempotent less C* algebra?
Nov 7, 2016 at 18:50 comment added Hannes Thiel @AliTaghavi What is your motivation to consider path connected and not just connected spectra?
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S Dec 28, 2015 at 14:21 history bounty started Ali Taghavi
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Nov 7, 2015 at 16:29 comment added jjcale Example of a connected C∗ algebra : See B.E. Blackadar. A simple unital projectionless C∗-algebra. J. Operator Theory, 5:63–71, 1981. By the comments of Hannes Thiel and Sam Evington this algebra is an example of a connected C* algebra. But is it also path connected (remark by Ali Taghavi) ?
Nov 7, 2015 at 10:28 history edited Ali Taghavi CC BY-SA 3.0
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S Nov 7, 2015 at 7:15 history bounty started Ali Taghavi
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Jun 13, 2015 at 21:40 history edited Ali Taghavi CC BY-SA 3.0
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Mar 4, 2015 at 15:13 comment added Sam Evington Hannes' observation can be improved: all elements of a C*-algebra with no non-trivial projections have connected spectrum. Indeed given an element with disconnected spectrum the holomorphic functional calculus gives a non-trivial idempotent. This will be similar to some self-adjoint idempotent (see Blackadar's K-Theory book) which will be non-trivial.
Mar 3, 2015 at 19:38 history edited Ali Taghavi CC BY-SA 3.0
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Feb 26, 2015 at 16:13 comment added Ali Taghavi @HannesThiel Thank you for the comment. So my second question leads to the following: What is an example of a projectionless simple $C^{*}$ algebra for which the spectrum of all elements are path connected.
Feb 25, 2015 at 18:46 comment added Hannes Thiel The spectrum of a nontrivial projection (i.e., nonzero and not the unit) is disconnected. Thus, a unital C*-algebra with the property you consider cannot contain any nontrivial projections. Conversely, if a C*-algebra contains a normal element with disconnected spectrum, then it contains a nontrivial projection. Thus, in a unital, simple C*-algebras without nontrivial projections (such as the Jiang-Su algebra), at least the spectrum of every normal element is connected.
Feb 7, 2015 at 0:45 comment added Ali Taghavi @JohannesHahn Thanks for your comment. If I am not mistaken, this algebra is simple iff the action of $G$ on $X$ does not have a nontrivial compact invariant set. Now how you controle the spectrum of elements?
Feb 7, 2015 at 0:37 comment added Johannes Hahn Well $\mathbb{C}$ is simple. But I assume you want something less trivial. A stab in the dark: One could imagine putting some group action on $C(X)$ such that none of its non-trivial ideals are $G$-invariant and hope that $C(X)\rtimes G$ is simple.
Feb 7, 2015 at 0:33 comment added Ali Taghavi @JohannesHahn yes I mean without closed two sided ideal.
Feb 7, 2015 at 0:31 comment added Johannes Hahn Oh you meant simple as in simple not as in easy...
Feb 7, 2015 at 0:30 comment added Ali Taghavi @JohannesHahn But $C(X)$ is not simple.
Feb 7, 2015 at 0:28 comment added Johannes Hahn An easy example: $C(X)$ for some path connected compactum $X$ is path connected in this sense because the spectrum of $f\in C(X)$ coincides with the range of $f$.
Feb 7, 2015 at 0:24 history asked Ali Taghavi CC BY-SA 3.0