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Timeline for Wang's C-subgroups and M-manifolds

Current License: CC BY-SA 3.0

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Feb 11, 2015 at 12:50 comment added Allen Knutson $K = Spin(5), S = Spin(2), C_K(S) = Spin(2) \times Spin(3), C_K(S)' = 1 \times Spin(3) = U.$ This may be the point at which you should write the author.
Feb 11, 2015 at 8:24 comment added David P Ok but Wang's setting is with $K$ simple.
Feb 10, 2015 at 19:49 comment added Allen Knutson $K = SU(2)^2, S = T \times 1, C_K(S) = T \times SU(2), C_K(S)' = 1 \times SU(2) = U$.
Feb 9, 2015 at 15:30 comment added David P I see your point. What if we add the assumption $U \neq 1$?
Feb 9, 2015 at 14:46 comment added Allen Knutson Let's take $K=SU(2)$, $S$ a maximal torus, $C_K(S) = S$, $U = 1 = S'$. So $U$ is semisimple and a C-subgroup. But any centralizer $Q$ contains a maximal torus, so $U\neq Q$.
Feb 8, 2015 at 8:37 comment added David P Ok, all tori are C-subgroups but there might be others and I'm asking about the semisimple ones.
Feb 7, 2015 at 17:40 comment added Allen Knutson According to your second paragraph, $U$ is a C-subgroup if $U' = Z(S)'$ for $S$ a torus. If $S$ is a maximal torus, then $Z(S) = S$ so $Z(S)' = S' = 1$. Then if $U$ is any torus, $U' = 1$ too, making it a C-subgroup.
Feb 7, 2015 at 16:56 comment added David P you mean every torus is a C-subgroup?
Feb 7, 2015 at 3:55 comment added Allen Knutson The centralizer of a torus contains a maximal torus. But any torus in $G$ (assuming $G$ is semisimple) satisfies your stated criterion, even if it isn't maximal. So I suspect you've misread something.
Feb 6, 2015 at 14:58 history asked David P CC BY-SA 3.0