Timeline for Convergence of random variables with hypergeometric distribution
Current License: CC BY-SA 3.0
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| Feb 3, 2015 at 13:09 | comment | added | user2173168 | Thank you for your answer. Here independence means, $\forall \epsilon>0$, there is an number $N(\epsilon)$, such that $\forall N>N(\epsilon)$, we have $|\mathbb{E}(xy/X-xy/Y)-1/a|<\epsilon$. Note that $\mathbb{E}(\frac{xy}{X})$ may tend to infinity, because $x$ can tend to infinity when $N$ grows, so this answer is not correct :-) | |
| Feb 3, 2015 at 13:01 | history | answered | Ori Gurel-Gurevich | CC BY-SA 3.0 |