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Feb 2, 2015 at 23:33 comment added M. Farrokhi D. G. The only assumption on the rings $R$ is associativity, and finiteness if any counting method is applicable.
Feb 2, 2015 at 23:29 vote accept M. Farrokhi D. G.
Feb 2, 2015 at 20:05 comment added Terry Tao Taking differences three times ($(x+1)^4-x^4 = (x+1)^2-x^2$, etc.) gives $24x=0$ for all $x$. EDIT: Actually, just taking $x=2$ gives the stronger claim $12=0$.
Feb 2, 2015 at 19:09 comment added zeb It isn't too hard to show that $2xy = 2yx$ for any $x,y$ in such a ring (it follows quickly from $2x^3 = 2x$).
Feb 2, 2015 at 18:22 comment added YCor I know people for which every ring is associative, unital, and commutative. I know people for which every ring is associative and unital, but not necessarily commutative. I know people for which rings are not assumed with any of these properties. In each of these communities, some people are convinced that their conventions are universal. Nevertheless I think it is useful to spare the reader from guessing which convention they use, it's really not a big effort.
Feb 2, 2015 at 15:20 comment added Qfwfq @YCor: usually rings are assumed to be associative and unital, but not necessarily commutative. I would assume the OP has that definition in mind..
Feb 2, 2015 at 14:10 answer added Zurab Silagadze timeline score: 14
Feb 2, 2015 at 13:59 comment added YCor Do you assume rings to be associative? unital?
Feb 2, 2015 at 10:51 history asked M. Farrokhi D. G. CC BY-SA 3.0