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Feb 1, 2015 at 8:21 comment added quinque Yes, relative cohomology are cohomology of homogenious space! And moreover there is a spectral sequence of a bundle. But I want to get this sequence for arbitrary Lie algebra. Here have to be purely algebraic approach for this.
Feb 1, 2015 at 0:50 comment added Qiaochu Yuan @quinque: that notion of relative Lie algebra cohomology is a little different. If you think of the cohomology of Lie algebras as an algebraic model of the de Rham cohomology of compact Lie groups $G$, then relative Lie algebra cohomology should be an algebraic model of the de Rham cohomology of homogeneous spaces $G/H$. Of course these can make sense if $H$ is not normal, but for group cohomology we want to compute the cohomology of the delooping of these spaces, and we just can't deloop homogeneous spaces in general.
Jan 31, 2015 at 21:57 comment added quinque math.ru.nl/~solleveld/scrip.pdf Here you can find a definition of relative Lie algebra cohomology. It is done by means of explicit complex but it is still a way to make sense of such kind of objects.
Jan 31, 2015 at 21:53 comment added quinque What you said is just that this approach does not work. But I mean something different. I even edited my question, wrote "analog of Lyndon–Hochschild–Serre spectral sequence".
Jan 31, 2015 at 21:41 history answered Qiaochu Yuan CC BY-SA 3.0