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Jan 29, 2015 at 8:35 comment added Mostafa - Free Palestine @MikhailBondarko thanks! You have completely resolved my problem.
Jan 29, 2015 at 8:13 comment added Mikhail Bondarko So, $H^{n-1}(X,Q)$ is a substructure in the corresponding cohomology of a smooth hyperplane section of $X$. Now you should just recall that the category of polarizable (pure) Hodge structures is Abelian semi-simple.
Jan 29, 2015 at 8:10 comment added Mostafa - Free Palestine @abx I mean it is a subquotient of a direct sum of Hodge structures of cohomology groups of curves. I think lefschetz hyperplane implies the above claim for $i< n-1$ but I am curious about the case $i=n-1$
Jan 29, 2015 at 7:57 comment added abx I am not sure I understand the question. Let us take $n=2$, $i=1$, so $X$ is a surface; what do you mean by "the Hodge structure on $H^1(X,\mathbb{Q})$ is generated by Hodge structures of curves"?
Jan 29, 2015 at 6:05 comment added Venkataramana This will follow from Lefschetz hyperplane section theorem
Jan 28, 2015 at 21:28 comment added dhy Not for $n=2$ and $i=1$; take $X$ the variety of lines on a smooth cubic threefold, then this is basically the main result of the Clemens-Griffiths proof of irrationality of smooth cubic threefolds. My guess is that for $i$ at least $2$ this is a hard question.
Jan 28, 2015 at 21:11 history asked Mostafa - Free Palestine CC BY-SA 3.0