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Jan 29, 2015 at 12:35 comment added Dominic van der Zypen Oops - I fell into the same trap... Thanks for the clarification!
Jan 29, 2015 at 11:34 history edited domotorp CC BY-SA 3.0
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Jan 29, 2015 at 11:27 comment added Ben Barber This is certainly a dominating set (if you pick one hyperedge containing each hypervertex then every hyperedge meets some hyperedge in the set), but is it a vertex cover? For that you would need that for every intersecting pair of hyperedges, one of the pair is in the cover. Or have I misunderstood?
Jan 28, 2015 at 15:38 vote accept Dominic van der Zypen
Jan 29, 2015 at 12:31
Jan 28, 2015 at 14:30 history answered domotorp CC BY-SA 3.0