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Jan 30, 2015 at 11:54 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 30, 2015 at 11:47 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 30, 2015 at 10:07 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 28, 2015 at 6:00 comment added Ali Taghavi @CarloBeenakker thank you very much for your very interesting answer.
Jan 28, 2015 at 5:27 vote accept Ali Taghavi
Jan 27, 2015 at 9:17 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 27, 2015 at 9:17 comment added Carlo Beenakker deleted "simplistic argument" for the first integral in my answer: the result for $p$ odd is obvious because contributions $\pm g$ to the integral cancel; the result for $p$ even follows without calculation from the fact that only eigenvalues $\pm 1$ of the orthogonal matrix $g$ contribute to the average of the trace (the complex eigenvalues average out to zero); for $n$ odd every $g$ has one such eigenvalue, so the average is one, for $n$ even and ${\rm det}\,g=+1$ there are no such eigenvalues but for ${\rm det}\,g=-1$ there are two, so the average is again one.
Jan 27, 2015 at 9:10 comment added Carlo Beenakker @WillSawin --- good point, this is not obvious, so I have removed the "simple argument", which was apparently too simple; for the record, it follows after this comment. Thanks for correcting me.
Jan 27, 2015 at 9:09 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 26, 2015 at 22:59 comment added Will Sawin Why do the complex eigenvalues average out to 0?
Jan 26, 2015 at 12:57 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 26, 2015 at 12:26 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 26, 2015 at 12:10 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 26, 2015 at 12:01 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 26, 2015 at 11:44 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 26, 2015 at 11:37 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 26, 2015 at 11:26 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 26, 2015 at 11:20 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 26, 2015 at 11:09 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 26, 2015 at 10:56 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 26, 2015 at 9:53 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 26, 2015 at 9:34 history answered Carlo Beenakker CC BY-SA 3.0