Timeline for Showing existence of positive weak solution of a PDE by CoV
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 27, 2015 at 18:21 | comment | added | Craig | actually omit above idea. I guess with this approach minimizer would always be nonpositive... | |
| Jan 27, 2015 at 17:55 | comment | added | Craig | maybe try replacing $$\int_\Omega |u| dx$$ with $\int_\Omega (u)_+ dx$... maybe ??? | |
| Jan 25, 2015 at 23:55 | comment | added | JumpJump | @JLA Oh I see. Yes, but that $k$ does not matter for me now. All I need is a weak solution. | |
| Jan 25, 2015 at 23:54 | comment | added | Josh Lackman | Sure, but I thought you wanted a solution of $-\Delta u+\alpha=u^q\,,$ not $-\Delta u+\alpha=ku^q$ for some $k\,.$ | |
| Jan 25, 2015 at 23:53 | comment | added | JumpJump | @JLA weak solution is enough, since we could use boot-strap to get classical solution | |
| Jan 25, 2015 at 23:53 | history | edited | JumpJump | CC BY-SA 3.0 |
added 6 characters in body
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| Jan 25, 2015 at 23:53 | comment | added | JumpJump | @JLA the problem is that if $u=0$ on a positive set, then term $(1)$ does not make sense right? | |
| Jan 25, 2015 at 23:51 | comment | added | Josh Lackman | Why is this the last step? You would get that $-\Delta u+\alpha=ku^q$ weakly, which doesn't seem to be exactly what you want. | |
| Jan 25, 2015 at 16:36 | history | asked | JumpJump | CC BY-SA 3.0 |