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Jan 29, 2015 at 22:51 vote accept Clay Cordova
Jan 29, 2015 at 22:50 vote accept Clay Cordova
Jan 29, 2015 at 22:51
Jan 25, 2015 at 16:07 comment added Noam D. Elkies You're welcome. For other $j$ there doesn't seem to be such a nice formula, except in the roughly-complementary case of $j=k-1$. Otherwise the power-series coefficients, written as polynomials in $N$, are generally irreducible once you remove the factor of $N$. (For $j=1$ they factor completely, which soon led me to surmise the formula above.)
Jan 25, 2015 at 13:35 comment added Clay Cordova Thanks Noam! I will look into this idea. Does anything similar work in the case j>1?
Jan 25, 2015 at 5:52 history answered Noam D. Elkies CC BY-SA 3.0