Timeline for Is $\mathcal{K}(H)$ injective $\mathcal{B}(H)$-module?
Current License: CC BY-SA 4.0
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| S Dec 23, 2020 at 21:06 | history | bounty ended | CommunityBot | ||
| S Dec 23, 2020 at 21:06 | history | notice removed | CommunityBot | ||
| Dec 15, 2020 at 20:15 | history | edited | YCor |
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| Dec 15, 2020 at 19:47 | history | edited | Norbert | CC BY-SA 4.0 |
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| S Dec 15, 2020 at 19:43 | history | bounty started | Norbert | ||
| S Dec 15, 2020 at 19:43 | history | notice added | Norbert | Canonical answer required | |
| Dec 15, 2020 at 19:41 | history | edited | Norbert | CC BY-SA 4.0 |
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| Jul 1, 2016 at 7:08 | answer | added | Norbert | timeline score: 2 | |
| Jan 27, 2015 at 7:38 | history | edited | Norbert | CC BY-SA 3.0 |
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| Jan 26, 2015 at 15:34 | comment | added | Norbert | @TomekKania, I've added the definition. | |
| Jan 26, 2015 at 15:32 | history | edited | Norbert | CC BY-SA 3.0 |
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| Jan 26, 2015 at 14:42 | comment | added | Tomasz Kania | Norbert, would you mind recalling your definition of injectivity? | |
| Jan 26, 2015 at 12:35 | history | edited | Norbert |
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| Jan 25, 2015 at 1:10 | comment | added | Norbert | @DavidHandelman, I'm interested in functional analytic version of injectivity. Anyway thank you for mentioning purely algebraic case also. | |
| Jan 25, 2015 at 1:07 | comment | added | David Handelman | Or do you mean, injective in the ring-theoretic sense; assuming $K(H)$ means the compact operators on the Hilbert space $H$, the answer is no, since it is an essential ideal in $B(H)$. | |
| Jan 25, 2015 at 0:46 | history | edited | Norbert | CC BY-SA 3.0 |
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| Jan 25, 2015 at 0:44 | comment | added | Norbert | Imean classical relative injectivity. The answer is, clearly, no for strict injectivity. | |
| Jan 25, 2015 at 0:41 | comment | added | Yemon Choi | Is this injective in the sense of Helemskii's classical theory, or strict injectivity (cf. White, Proc LMS) | |
| Jan 25, 2015 at 0:21 | history | asked | Norbert | CC BY-SA 3.0 |