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Apr 21, 2016 at 19:58 comment added Saal Hardali @ಠ_ಠ Well, what you describe gives a an adjoint pair so it must be the one by uniqueness.
Jan 20, 2016 at 8:07 comment added ಠ_ಠ I assume that the right-adjoint functor $\Gamma: \mathsf{LieAlg} \to \mathsf{LieGrp}$ is the usual mapping of a Lie algebra to its simply connected Lie group?
Apr 10, 2015 at 2:15 vote accept ಠ_ಠ
Apr 10, 2015 at 2:15
S Jan 23, 2015 at 17:07 history answered Neil Strickland CC BY-SA 3.0
S Jan 23, 2015 at 17:07 history made wiki Post Made Community Wiki by Neil Strickland