Skip to main content
5 events
when toggle format what by license comment
Jan 22, 2015 at 19:38 comment added Lior Bary-Soroker The irreducibility for most $\epsilon=1/n$, say, is given by Hilbert's irreducibility theorem.
Jan 22, 2015 at 16:49 vote accept Balazs Strenner
Jan 21, 2015 at 16:16 answer added Ilya Bogdanov timeline score: 4
Jan 21, 2015 at 15:42 comment added Yaakov Baruch Just an idea: what about picking $n$ rationals $q_i$ wherever you like, then looking at $P(X)=\prod_i{(X-q_i)}+\epsilon$. Can't we find a small rational $\epsilon$ such that $P(X)$ is irreducible and its roots within some given $\delta$ of the $q_i$'s?
Jan 21, 2015 at 15:31 history asked Balazs Strenner CC BY-SA 3.0