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Timeline for Values of cusp forms at q = 1 ?

Current License: CC BY-SA 2.5

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Nov 6, 2010 at 11:15 vote accept Franz Lemmermeyer
Mar 27, 2010 at 4:02 comment added KConrad Oh, and the convergence of $L(s)$ for $s$ with real part greater than 5/6 uses the elliptic modularity theorem.
Mar 27, 2010 at 4:01 comment added KConrad Voloch is right: this $\sqrt{2}$ is related to partial Euler product behavior as $s$ tends to 1, not to the Dirichlet series representation for $L(s)$, which in fact converges for $s$ with real part greater than 5/6 (so at $s=1$). If you replace elliptic curve $L$-functions with Hecke $L$-functions for a quadratic character, you can turn the unexpected $\sqrt{2}$ into $1/\sqrt{2}$ with the Euler product as $s$ tends to $1/2$. Oh, and all such Euler product convergence implies GRH so you can numerically test this stuff and see it happen but you'll never unconditionally prove it.
Mar 26, 2010 at 17:52 comment added Felipe Voloch @Kevin, you mean Goldfeld, not Szpiro. What he proved was to do with $\prod N_p/p$, the quantity originally computed by Birch and Swinnerton-Dyer. See: ams.org/mathscinet/search/… I don't think this is related with $\sum a_n/n$ which does seem to converge conditionally to $L(1)$.
Mar 26, 2010 at 16:15 comment added Marty I don't think I've got the analytic expertise for that one. But I saw it, and I'm curious about any answers from others.
Mar 26, 2010 at 15:53 comment added Kevin Buzzard Based on your comments Marty, you might want to take a stab at mathoverflow.net/questions/19410/… which may be talking about a similar issue?
Mar 26, 2010 at 15:52 comment added Kevin Buzzard Sounds like I have indeed got the wrong end of the stick then :-) Apologies.
Mar 26, 2010 at 15:23 comment added Marty But here I'm looking at $f(z)$ as $z$ approaches $1$, via certain paths in the upper half-plane. These values have almost nothing in common with the values of the Dirichlet series as $s$ approaches zero. For cusp forms, the limits I'm talking about are in the same spirit as the convergent integral representation of the L-function.
Mar 26, 2010 at 15:17 comment added Kevin Buzzard Somehow it would surprise me if $f(q)$ really did tend to $L(E,0)$ in any reasonable sense, because isn't it a result of Szpiro that if $\sum_n a_n.n^{-s}$ converges as $s$ tends to 1, then it won't converge to $L(E,1)$ but rather to something like $\sqrt{2}$ times this? I forgot what he actually proved unfortunately. Somehow if you can't get it right at 1 with 'naive' methods, what chance have you of getting it right at 0? Or do you think I've got the wrong end of the stick?
Mar 26, 2010 at 15:13 history answered Marty CC BY-SA 2.5