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Jan 20, 2015 at 17:26 comment added Stanley Yao Xiao That comment is satisfactory for my purposes, thank you
Jan 19, 2015 at 21:53 comment added Lucia @juan When the $a_n$ are distinct, then from the conditions it follows that very few of the $a_n$ can be multiples of a prime $p$ with $p\le x^{1/10}$ say. But then the number of integers up to $x$ composed of primes larger than $x^{1/10}$ is $O(x/\log x)$.
Jan 19, 2015 at 20:41 comment added juan @Lucia What is the problem in the case of the $a_n$ distinct? Do you need all the modules $m$ to get the contradiction?
Jan 19, 2015 at 20:19 comment added Lucia If the $a_n$ can have repeats, then you should just be able to repeat primes an appropriate number of times. If the $a_n$ are distinct, then there is no such sequence. Perhaps you could clarify the question.
Jan 19, 2015 at 18:39 history asked Stanley Yao Xiao CC BY-SA 3.0