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Jan 21, 2015 at 7:57 comment added Dominic van der Zypen That's right, Ramiro, and thanks for your remark. My question should have been: is there any reason why this sharper version (ultraparacompactness as opposed to paracompactness) doesn't work? Maybe ultraparacompactness is also open...
Jan 20, 2015 at 14:01 comment added Ramiro de la Vega You probably know that whether $\Box (\omega + 1)^\omega$ is paracompact (in ZFC), is a long-standing open problem.
Jan 20, 2015 at 6:49 comment added Dominic van der Zypen Please feel free to edit the question and write it in a more understandable way
Jan 19, 2015 at 22:08 comment added Gerald Edgar It seems bad to me to write this like an ordinal power. But what do I know.
Jan 19, 2015 at 16:36 history asked Dominic van der Zypen CC BY-SA 3.0