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Jan 21, 2013 at 15:20 comment added Carlo Mantegazza T is Lipschitz, hence zero-sets go to zero-sets
Mar 27, 2010 at 17:43 comment added Nicolò Yes, but there are several things to show..
Mar 27, 2010 at 1:11 comment added François G. Dorais @Nicolò: Cover $N$ with balls of very small total measure and think about what $T$ does to each ball...
Mar 26, 2010 at 22:59 comment added Nicolò I've thought it was immediate to show that linear bijection are Leb-Leb measurable, but thinking a little more on it there is a thing to show: if $T$ is a linear bijection and $N$ is a Borelian of null measure, is $T(N)$ of null measure?
Mar 26, 2010 at 22:39 comment added Regenbogen Why was this answer accepted? Of course this answer was very helpful; but it doesn't actually answer the question.
Mar 26, 2010 at 22:37 vote accept Nicolò
Mar 26, 2010 at 22:56
Mar 26, 2010 at 13:31 history answered Robin Chapman CC BY-SA 2.5