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Jan 18, 2015 at 2:28 vote accept user65993
Jan 17, 2015 at 2:25 answer added Misha timeline score: 6
Jan 15, 2015 at 13:45 comment added user65993 Prof. de Cornulier: Thank you. So it appears that my slightly stronger question may be open as well (or false), but certainly that no proof is known. Do you know of a reference to read more about these specific examples?
Jan 15, 2015 at 10:03 comment added YCor It's an open question whether $SL_{3}(\mathbf{Q}_p)$ (or equivalently its Euclidean building) has a quasi-isometric embedding into a product of trees (and more generally $SL_d(\mathbf{Q}_p)$ or $SL_d(\mathbf{R})$ for some/any $d\ge 3$).
Jan 15, 2015 at 9:49 comment added Alain Valette You're right, I overlooked the surjectivity issue. I leave my comment however, as a very partial contribution.
Jan 14, 2015 at 23:47 history edited user65993
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Jan 14, 2015 at 23:10 comment added user65993 Prof. Valette: Thank you for the response. I don't see how Theorem 1.1.2 in Kleiner-Leeb answers my question, as the quasi-isometries considered in that theorem are assumed to be (coarsely) surjective, whereas I am only interested in an embedding result. (Or did I misunderstand? I reiterate my lack of expertise re: buildings.)
Jan 14, 2015 at 22:45 comment added Alain Valette I think taking $p=1$ is prevented by the Kleiner-Leeb result on quasi-isometric rigidity of Euclidean buildings: see Theorem 1.1.2 in math.nyu.edu/~bkleiner/symm.pdf
Jan 14, 2015 at 21:04 review First posts
Jan 14, 2015 at 21:29
Jan 14, 2015 at 21:02 history asked user65993 CC BY-SA 3.0