Timeline for Products of Cohen forcings
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 2, 2019 at 15:58 | vote | accept | Yair Hayut | ||
| Jun 28, 2019 at 5:52 | answer | added | Elliot Glazer | timeline score: 8 | |
| Feb 25, 2015 at 5:36 | answer | added | Mohammad Golshani | timeline score: 7 | |
| Jan 19, 2015 at 10:24 | answer | added | Yair Hayut | timeline score: 5 | |
| Jan 15, 2015 at 11:56 | comment | added | Avshalom | @JoelDavidHamkins Thanks for the details of the $\omega$ case below in your answer; so at least the assertion is consistent for some uncountable cardinals. If one could decompose the full-support $\lambda$-product appropriately, then one would have an answer. | |
| Jan 15, 2015 at 2:58 | comment | added | Monroe Eskew | Related: math.stackexchange.com/questions/674824/levy-collapse-gone-bad | |
| Jan 15, 2015 at 2:31 | answer | added | Joel David Hamkins | timeline score: 6 | |
| Jan 15, 2015 at 2:04 | comment | added | Joel David Hamkins | @Avshalom, if $(2^{\aleph_0})^V$ is collapsed to $\omega$ (which is not hard to see), and this is the same as $(2^\lambda)^V$, then of course it follows that $(2^\lambda)^V$ is also collapsed, by the first $\omega$ many coordinates already. | |
| Jan 14, 2015 at 23:24 | comment | added | Avshalom | To help me, please: if for $\lambda > \aleph_0, 2^\lambda = 2^{\aleph_0}$ in the ground model, will Kunen's result apply? | |
| Jan 14, 2015 at 18:06 | history | asked | Yair Hayut | CC BY-SA 3.0 |