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Jan 16, 2015 at 6:02 comment added Allen Knutson Yes, that's the one. It'll tell you that $S_x \cap g\cdot S_y$ is transverse for general $g$. This intersection changes to something isomorphic if you multiply $g$ on the left by $B_-$, and changes not at all if you multiply it on the right by $B_-$. So we can reduce $g$ from being in the generic Bruhat stratum of $G$ to actually being $w_0$, and still maintain transversality.
Jan 15, 2015 at 20:03 comment added Qiao Thanks! Are you referring to this paper of Kleiman 'The Transversality of a General Translate', or another paper? How does this paper immediately imply that Richardson varieties are nice and have dimension $l(w_1) - l(w_2)$?
Jan 14, 2015 at 18:18 vote accept Qiao
Jan 14, 2015 at 18:15 vote accept Qiao
Jan 14, 2015 at 18:18
Jan 14, 2015 at 17:20 history answered Allen Knutson CC BY-SA 3.0