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Jan 17, 2015 at 7:54 vote accept Ali Taghavi
Jan 14, 2015 at 20:11 answer added Victor Kleptsyn timeline score: 11
Jan 14, 2015 at 19:47 answer added Alejandro timeline score: 4
Jan 14, 2015 at 17:47 comment added Ryan Budney The elements that are not in the closure of the periodic elements, they're things like homeomorphisms that have some non-empty fixed-point sets, but the fixed point set is not the entire circle. So on the intervals between the fixed points they're shift operations.
Jan 14, 2015 at 15:14 comment added Alejandro @AliTaghavi notice that if periodic orbits of $g$ are dense, then $g\in Y$. In fact, any periodic orientation-reversing homeo has period $2$, and hence there is no orientation-reversing map in $\overline{Y}\setminus Y$. On the other hand, every periodic orbit of an orientation-preserving homeo has the same period. So, any $g$ with dense periodic orbits must be periodic itself.
Jan 14, 2015 at 10:37 history edited Ali Taghavi CC BY-SA 3.0
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Jan 14, 2015 at 10:02 comment added Ali Taghavi @Hachino Any way, thank you for your comment:)
Jan 14, 2015 at 9:52 comment added Hachino I don't know, that's just something your question reminded me of. I am no expert in DS, sorry.
Jan 14, 2015 at 9:44 comment added Ali Taghavi @Hachino thanks for your comment. Is the situation similar to $g=$ irrational rotation? Is there an example of a $g$ for which periodic orbits are dense, in contrast to irrational rotation? Could you please more explain on your comment?
Jan 14, 2015 at 9:40 comment added Hachino If it is indeed the case that $g$ is a homeomorphism, then this should help you with $2)$.
Jan 14, 2015 at 9:23 history edited Ali Taghavi CC BY-SA 3.0
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Jan 14, 2015 at 9:17 history asked Ali Taghavi CC BY-SA 3.0