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Apr 22, 2010 at 16:55 vote accept Randy Brown
Mar 26, 2010 at 11:13 comment added Charles Siegel To elaborate on jvp's point slightly, you can't even define the degree of a divisor on a variety that isn't a curve. On a curve, you count the points. But what about on a surface? You would need the degrees of curves, which are less obvious. However, the self-intersection of a curve is well defined and gives the right answer.
Mar 26, 2010 at 4:23 vote accept Randy Brown
Apr 22, 2010 at 16:54
Mar 26, 2010 at 4:17 history answered Jorge Vitório Pereira CC BY-SA 2.5