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Jan 16, 2015 at 1:09 comment added Samuel M @QiaochuYuan Thank you, it makes more sense now.
Jan 14, 2015 at 12:09 comment added Qiaochu Yuan @Samuel: yes (or one might instead mean Hochschild cochains).
Jan 14, 2015 at 10:23 comment added Samuel M Thank you, that was very well-explained, it's the derived setting I was most interested in, so in the derived setting the formula $End_{A \otimes A^{op}}(A)$ is basically just Ext$^{\bullet}_{A \otimes A^{op}}(A,A)$ = Hochschild cohomology of $A$ with coefficients in $A%)$? Or am I using the term derived in the wrong context?
Jan 13, 2015 at 3:11 history answered Noah Snyder CC BY-SA 3.0