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Timeline for Simple Spectrum of Jacobi matrices

Current License: CC BY-SA 3.0

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Jun 26, 2015 at 9:54 answer added Twi timeline score: 1
Jan 22, 2015 at 3:03 review First posts
Jan 22, 2015 at 3:17
Jan 13, 2015 at 1:00 answer added Christian Remling timeline score: 0
Jan 12, 2015 at 23:49 answer added Alexandre Eremenko timeline score: 4
Jan 12, 2015 at 20:59 comment added Adrien Hardy Because the spectrum of an nxn truncation of a Jacobi matrix has for eigenvalues the zeroes of a degree n orthogonal polynomial, read the literature on OPs.
Jan 12, 2015 at 20:27 comment added Jiao Guo @ChrisGodsil it just means that if you take the upper (n-1)x(n-1) submatrix of $A$, then the eigenvalues between this matrix and $A$ are interlacing. So between any eigenvalues of $A$ is one of the submatrix, but I guess that this property is more or less unrelated to this question.
Jan 12, 2015 at 20:20 comment added Chris Godsil What do you mean by "spectrum is interlacing"?
Jan 12, 2015 at 20:14 history edited Jiao Guo CC BY-SA 3.0
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Jan 12, 2015 at 19:21 history asked Jiao Guo CC BY-SA 3.0