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Apr 13, 2017 at 12:57 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Jan 13, 2015 at 2:07 comment added Włodzimierz Holsztyński Now that the answer to the Dominic's Question is YES, it's time to look for applications (perhaps outside of combinatorics too, perhaps especially outside; we have here infinite combinatorics anyway).
Jan 13, 2015 at 2:04 comment added Włodzimierz Holsztyński @bof is right. In particular, given a flag complex $\ (V\ E),\ $ one defines the lines of the induced graph as pairs $\ \{a\ b\}\in\binom V2\ $ exactly such that $\ \{a\ b\}\ $ is not a flag (not a hypergraph edge). Somehow I'd overlooked bof's observation for a while (sorry), and later made an equivalent onbservation but in the terms of a dual graph, so I talked about cliques instead of independent sets--but it's essentially the same.
Jan 12, 2015 at 12:58 vote accept Dominic van der Zypen
Jan 12, 2015 at 12:11 answer added Włodzimierz Holsztyński timeline score: 2
Jan 12, 2015 at 8:05 comment added Dominic van der Zypen Because it ends with not minimal, and the title says "minimality condition"? :)
Jan 10, 2015 at 7:44 comment added Włodzimierz Holsztyński I like the last word of the Question: mimimal :-)
Jan 9, 2015 at 10:10 comment added Dominic van der Zypen That's correct bof: the family of all independent sets of some graph $G=(V,E)$ does form a flag complex. On the other hand, given a flag complex, I would have to think about the question whether there is a graph whose collection of independent sets gives back the edge set of the original flag complex.
Jan 9, 2015 at 10:07 comment added Dominic van der Zypen Thanks Wlodimierz - I deleted my comment and have recorded your information, you can delete yours now too
Jan 9, 2015 at 10:04 comment added bof What is the difference in meaning between "$(V,E)$ is a flag complex" and "$E$ is the family of all independent sets for some graph on the vertex set $V$"? What am I missing?
Jan 9, 2015 at 9:49 comment added Dominic van der Zypen Just a short answer: the question is an end to itself; I am toying around with (strongly) minimal coverings in hypergraphs in general.
Jan 9, 2015 at 9:46 history edited Dominic van der Zypen CC BY-SA 3.0
Added note after question
Jan 9, 2015 at 9:46 comment added Włodzimierz Holsztyński Is the present problem an end to itself or is it a part of a larger picture (or an intermediate step, or has some ready applications)?
Jan 9, 2015 at 8:59 history edited Dominic van der Zypen CC BY-SA 3.0
Fixed typo in condition 1.
Jan 9, 2015 at 8:34 history asked Dominic van der Zypen CC BY-SA 3.0