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Jan 8, 2015 at 18:59 comment added Benjamin Steinberg At the moment I only remember the proof if there are only finitely many prime divisors of the order of the group.
Jan 8, 2015 at 18:56 answer added Benjamin Steinberg timeline score: 4
Jan 8, 2015 at 18:46 comment added Benjamin Steinberg The paper only gives the proof for relatively free groups because we were interested in that. My memory seems to be we had a more general proof that we left out because we had a slicker proof for the relatively free case. The problem is I don't recall it yet from 10 years ago!
Jan 8, 2015 at 18:33 comment added Pablo @BenjaminSteinberg I think that your arguments work only for varieties of groups.
Jan 8, 2015 at 18:17 comment added Benjamin Steinberg I studied this 10 years ago with Auinger. I believed we proved it has an open normal free pro-p subgroup such that the quotient is a finite abelian group of exponent dividing p-1 but I will double check
Jan 8, 2015 at 17:05 history asked Pablo CC BY-SA 3.0