Skip to main content
4 events
when toggle format what by license comment
Jan 8, 2015 at 14:50 comment added abx Yes to both questions. Note that $\hat{X}= \mathrm{Spec}(S)$, so $\hat{X}$ Cohen-Macaulay $\Leftrightarrow \ S$ Cohen-Macaulay.
Jan 8, 2015 at 13:23 vote accept Hans
Jan 8, 2015 at 13:23 comment added Hans thank you. is it true that since $X$ is Cohen-Macaulay, I just have to check whether $S$ localized at the irrelevant ideal is Cohen-Macaulay? And is it correct that $X$ is arithmetically Cohen-Macaulay if and only if the affine cone $\hat{X}$ is Cohen-Macaulay?
Jan 8, 2015 at 13:03 history answered abx CC BY-SA 3.0