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Apr 5, 2015 at 22:04 comment added pavel I think that all required tools have non-ergodic versions, see arxiv.org/abs/0905.0516
Mar 1, 2015 at 5:15 vote accept Mathemagician
Mar 1, 2015 at 5:15 comment added Mathemagician Thank you. I have actually found a simple proof not long after posting this question, but had no time to post it here. It is different to yours, but strictly requires the ergodicity of X. I was wondering if your proof requires the ergodicity of X?
Jan 7, 2015 at 13:46 history answered pavel CC BY-SA 3.0