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Jan 8, 2015 at 19:31 comment added Yaakov Baruch I apologize for bumping up this answer one last time. I wanted to make the attached image clearer.
Jan 8, 2015 at 19:28 history edited Yaakov Baruch CC BY-SA 3.0
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Jan 8, 2015 at 10:11 comment added Yaakov Baruch There is more case for $r=4$, corresponding to $(d_1, p_1, d_2, p_2)=(7, 12, 1, 6)$, for which $a=b=(\sqrt{3}+1)/2$.
Jan 8, 2015 at 1:56 history edited Yaakov Baruch CC BY-SA 3.0
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Jan 6, 2015 at 22:25 history answered Yaakov Baruch CC BY-SA 3.0