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Jul 6, 2016 at 3:46 review Reopen votes
Jul 6, 2016 at 11:45
May 3, 2015 at 16:31 review Reopen votes
May 3, 2015 at 18:25
May 3, 2015 at 16:22 comment added Yemon Choi I think on reflection that the edits by the OP, and his/her responses to the comments and the answer, justify re-opening the question
May 3, 2015 at 16:21 history edited Yemon Choi CC BY-SA 3.0
reformatted for legibility; spelling corrections and minor tweaks to grammar
Jan 4, 2015 at 21:37 comment added Donu Arapura Well we don't care about the Zariski topology because we want to do classical analysis on it, we care about it because we can define sheaves on it. After that, a whole wide world opens up.
Jan 4, 2015 at 21:29 history closed Fernando Muro
Daniel Loughran
Dietrich Burde
abx
Stefan Kohl
Opinion-based
Jan 4, 2015 at 21:00 comment added truebaran Not only I'm aksing for such an explanation but I would also like to know why algebraic geometers care so much about spaces which are not Hausdorff. As I explained before: in noncommutative topology when some space is non Hausdorff one rather try to investigate it by associating some algebra to it and then investigate this algebra. This is the first point. Second is that due to the existence of convergent nets with more than one limit my natural reaction to non Hausdorff spaces is to dismiss them as being pathological. By the way: maybe I should add "soft-question" tag to this question?
Jan 4, 2015 at 20:47 comment added Yemon Choi I still don't understand what it is you seek in an "interpretation" of non-Hausdorff topological spaces arising in algebraic geometry. Are you merely asking for some conceptual explanation of why these spaces are non-Hausdorff?
Jan 4, 2015 at 19:37 answer added Simon Rose timeline score: 8
Jan 4, 2015 at 19:03 review Close votes
Jan 4, 2015 at 21:29
Jan 4, 2015 at 18:32 history edited truebaran CC BY-SA 3.0
I tried to make my vaque question slightly more precise but I'm afraid that it still remains vaque...
Jan 4, 2015 at 18:07 comment added David Benjamin Lim The analog of Hausdorffness in algebraic geometry is the notion of a separated scheme. Definition: A scheme $X$ is separated if the diagonal $X \to X \times X$ is a closed immersion. Now prove the following. Let $Y$ be a topological space. Then $Y$ is Hausdorff iff the diagonal $\{(y,y) : y\in Y\}$ is closed in the product topology on $Y \times Y$.
Jan 4, 2015 at 18:06 comment added Yemon Choi "What is the meaning of" is not a well-defined question. Neither is "how to interpret". Can you try to rephrase your question to be more precise?
Jan 4, 2015 at 18:00 history asked truebaran CC BY-SA 3.0