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Apr 28, 2016 at 8:35 comment added Fedor Petrov Assume that there is some construction on the plane $\pi$ which given parabola $\gamma$ gives its focus $F$. Let $T$ be projective map for which $T(\gamma)$ is a parabola again, but $T(F)$ is not it's focus. Apply the same construction to $T(\gamma)$ on $T(\pi)$, we get $T(F)$. Contradiction.
Apr 28, 2016 at 7:39 comment added Ivan Meir You need to define the focus and by doing so I guess you might already see that this is not projective. Also there are points that are always preserved by a projective transform, the point at infinity in the case of the parabola so this contradicts your final statement. Can you modify it to make it always hold?
Apr 28, 2016 at 7:32 comment added Ivan Meir How do you prove this?
Jan 1, 2015 at 20:02 history edited Fedor Petrov CC BY-SA 3.0
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Dec 31, 2014 at 17:38 vote accept Victor
Dec 31, 2014 at 17:38 comment added Victor Fantastic! It's very easy and hence beautiful and hence genius! Happy New Year
Dec 31, 2014 at 16:48 history answered Fedor Petrov CC BY-SA 3.0