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Jan 6, 2015 at 2:52 answer added math110 timeline score: 2
Jan 4, 2015 at 15:43 vote accept math110
Jan 3, 2015 at 22:32 history rollback Christian Remling
Rollback to Revision 9
Jan 3, 2015 at 22:32 history rollback Christian Remling
Rollback to Revision 1
Jan 3, 2015 at 5:22 comment added Christian Remling I believe the calculation for $JPJ^t$ (and thus the whole identity) is not correct.
Jan 2, 2015 at 5:00 answer added Włodzimierz Holsztyński timeline score: 0
Jan 2, 2015 at 2:46 history edited math110 CC BY-SA 3.0
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Jan 1, 2015 at 21:20 comment added Wolfgang You might want to write the tridiagonal matrix more suggestively using \ddots: $$JPJ^T=J^TQJ=\begin{bmatrix} 2&-2&0&\cdots&0\\ -2&4&-3&\ddots\qquad&0\\ 0&-3 &6&\ddots\qquad&0\\ \vdots&&\ddots\qquad&\ddots\ \qquad&\vdots\\ 0&\cdots&-(n-2)&2(n-1)&-(n-1)\\ 0&\cdots&0&-(n-1)&2n \end{bmatrix}$$
Jan 1, 2015 at 19:14 answer added Christian Remling timeline score: 16
Jan 1, 2015 at 2:51 history edited math110 CC BY-SA 3.0
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Dec 31, 2014 at 3:51 history edited math110 CC BY-SA 3.0
edited title
Dec 31, 2014 at 2:27 history edited math110 CC BY-SA 3.0
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Dec 31, 2014 at 0:17 history reopened Vladimir Dotsenko
Daniel Litt
Nate Eldredge
Francois Ziegler
Bjørn Kjos-Hanssen
S Dec 30, 2014 at 23:24 history suggested Tadashi CC BY-SA 3.0
Improved the English writing of the question
Dec 30, 2014 at 23:12 review Suggested edits
S Dec 30, 2014 at 23:24
Dec 30, 2014 at 22:22 review Reopen votes
Dec 30, 2014 at 23:53
Dec 30, 2014 at 18:54 history closed Yemon Choi
Dima Pasechnik
Per Alexandersson
Stefan Kohl
Will Jagy
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Dec 30, 2014 at 16:56 history edited math110 CC BY-SA 3.0
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Dec 30, 2014 at 16:24 history edited math110 CC BY-SA 3.0
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Dec 30, 2014 at 16:21 review Close votes
Dec 30, 2014 at 18:57
Dec 30, 2014 at 16:19 history edited math110 CC BY-SA 3.0
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Dec 30, 2014 at 16:00 history asked math110 CC BY-SA 3.0