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Apr 13, 2017 at 12:19 history edited CommunityBot
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Jan 5, 2015 at 11:43 comment added Lewis Zhang @ChangyuGuo Thank you for the book you recommend. The proof in that book is very clear. However, the definition of topological dimension there is defined for separable metrizable topological spaces. But it is enough for me.
Jan 1, 2015 at 17:35 comment added Changyu Guo If you look for a proof of the fact that for a metric space, the Hausdorff dimension is always greater than or equal to the topological dimension, there is a nice book by Juha Heinonen, Lecture notes on analysis on metric spaces 2001.
Dec 31, 2014 at 13:06 vote accept Lewis Zhang
Dec 30, 2014 at 22:48 history edited Lewis Zhang CC BY-SA 3.0
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Dec 30, 2014 at 14:34 answer added Pablo Shmerkin timeline score: 13
Dec 30, 2014 at 14:10 history edited Lewis Zhang CC BY-SA 3.0
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Dec 30, 2014 at 14:03 history asked Lewis Zhang CC BY-SA 3.0