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Mar 18, 2019 at 16:37 history edited YCor
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Oct 24, 2015 at 4:15 vote accept Tadashi
Oct 23, 2015 at 16:36 answer added David Towers timeline score: 3
Dec 29, 2014 at 17:35 history made wiki Post Made Community Wiki by Todd Trimble
Dec 29, 2014 at 16:43 comment added YCor Note that this nilpotency result is trivial for positive gradings ($\mathfrak{g}_n=0$ for all $n<0$ and all $n\ge n_0$), but the latter trivially holds for all algebras (module + bilinear law) while the former doesn't, with simple counterexamples.
Dec 29, 2014 at 16:36 comment added YCor One example: if a Leibniz algebra (over any commutative ring) admit a grading in $\mathbf{Z}$ such that $\mathfrak{g}_n=0$ for all $|n|\ge n_0$ for some $n_0$ and $\mathfrak{g}_0=0$, then $\mathfrak{g}$ is nilpotent. (See my answer to mathoverflow.net/questions/90964/… )
Dec 29, 2014 at 3:53 history asked Tadashi CC BY-SA 3.0